4x^2+y^2=20

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Solution for 4x^2+y^2=20 equation: 


Simplifying
4x2 + y2 = 20

Solving
4x2 + y2 = 20

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-1y2' to each side of the equation.
4x2 + y2 + -1y2 = 20 + -1y2

Combine like terms: y2 + -1y2 = 0
4x2 + 0 = 20 + -1y2
4x2 = 20 + -1y2

Divide each side by '4'.
x2 = 5 + -0.25y2

Simplifying
x2 = 5 + -0.25y2

Reorder the terms:
-5 + x2 + 0.25y2 = 5 + -0.25y2 + -5 + 0.25y2

Reorder the terms:
-5 + x2 + 0.25y2 = 5 + -5 + -0.25y2 + 0.25y2

Combine like terms: 5 + -5 = 0
-5 + x2 + 0.25y2 = 0 + -0.25y2 + 0.25y2
-5 + x2 + 0.25y2 = -0.25y2 + 0.25y2

Combine like terms: -0.25y2 + 0.25y2 = 0.00
-5 + x2 + 0.25y2 = 0.00

The solution to this equation could not be determined.

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